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5x^2-10x-50=29
We move all terms to the left:
5x^2-10x-50-(29)=0
We add all the numbers together, and all the variables
5x^2-10x-79=0
a = 5; b = -10; c = -79;
Δ = b2-4ac
Δ = -102-4·5·(-79)
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{105}}{2*5}=\frac{10-4\sqrt{105}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{105}}{2*5}=\frac{10+4\sqrt{105}}{10} $
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