5x2+8x+3=(x+)(x+)

Solution for 5x2+8x+3=(x+)(x+) equation:

5x^2+8x+3=(x+)(x+)

We move all terms to the left:

5x^2+8x+3-((x+)(x+))=0

We add all the numbers together, and all the variables

5x^2+8x-((+x)(+x))+3=0

We multiply parentheses ..

5x^2-((+x^2))+8x+3=0


We calculate terms in parentheses: -((+x^2)), so:

(+x^2)

We get rid of parentheses

x^2

Back to the equation:

-(x^2)


We add all the numbers together, and all the variables

4x^2+8x+3=0

a = 4; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·4·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*4}=\frac{-12}{8}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*4}=\frac{-4}{8}
=-1/2
$