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5x^2+50x-6000=0
a = 5; b = 50; c = -6000;
Δ = b2-4ac
Δ = 502-4·5·(-6000)
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{122500}=350$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-350}{2*5}=\frac{-400}{10} =-40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+350}{2*5}=\frac{300}{10} =30 $
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