5x2+36x+24=0

Solution for 5x2+36x+24=0 equation:

5x^2+36x+24=0

a = 5; b = 36; c = +24;
Δ = b2-4ac
Δ = 362-4·5·24
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{51}}{2*5}=\frac{-36-4\sqrt{51}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{51}}{2*5}=\frac{-36+4\sqrt{51}}{10}
$