5x2+30x+25=0

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Solution for 5x2+30x+25=0 equation:



5x^2+30x+25=0
a = 5; b = 30; c = +25;
Δ = b2-4ac
Δ = 302-4·5·25
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-20}{2*5}=\frac{-50}{10} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+20}{2*5}=\frac{-10}{10} =-1 $

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