If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+12x-27=0
a = 5; b = 12; c = -27;
Δ = b2-4ac
Δ = 122-4·5·(-27)
Δ = 684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{684}=\sqrt{36*19}=\sqrt{36}*\sqrt{19}=6\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6\sqrt{19}}{2*5}=\frac{-12-6\sqrt{19}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6\sqrt{19}}{2*5}=\frac{-12+6\sqrt{19}}{10} $
| 12j+4=-8 | | 95=11t-4 | | 0.50x+8=16.75 | | 24-6=m-3m | | 3(3 − 3x) = 2(x + 3) − 30 | | 3/23=6/x | | -10t+10=-10-5t-9t | | 144=6(-1-5n) | | 3s-8=-14 | | 9x-10=7X24 | | 126+8x+6=180 | | 4-8x=-18 | | 2.5(4x+3.2)=3(5-x) | | 126=8x+6 | | (5x=1)(3x=7) | | 105-(5*100)=y | | 10+9(-m+8)=-7-1+m | | 2x-8=2/3(3x+3) | | 10x+8=15-3x | | 13=6-b | | -8x-3=-2x+10= | | -8x-3=-2x+10 | | 2(x-2)=-(x+7) | | 6(x-2)=-18x= | | 6(c+36)=625 | | 2=3.14×d | | 3(b+20)= | | 3(x−3)=5x−4+3(7−x | | 6x-8-2x=4 | | -6c-10=-10c+10 | | 2(x+3)=2+5x | | 2c-5=-45 |