5x2+10x+7=2

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Solution for 5x2+10x+7=2 equation: 



5x^2+10x+7=2

We move all terms to the left:

5x^2+10x+7-(2)=0

We add all the numbers together, and all the variables

5x^2+10x+5=0

a = 5; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-10}{10}=-1$

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