5x2(x-1)=4(3-x)-2x

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Solution for 5x2(x-1)=4(3-x)-2x equation: 



5x^2(x-1)=4(3-x)-2x

We move all terms to the left:

5x^2(x-1)-(4(3-x)-2x)=0

We add all the numbers together, and all the variables

5x^2(x-1)-(4(-1x+3)-2x)=0



We calculate terms in parentheses: -(4(-1x+3)-2x), so:

4(-1x+3)-2x

We add all the numbers together, and all the variables

-2x+4(-1x+3)

We multiply parentheses

-2x-4x+12

We add all the numbers together, and all the variables

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

5x^2(x-1)+6x-12=0

We move all terms containing x to the left, all other terms to the right

5x^2(x-1)+6x=12

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