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5x/x+4=3x+1
We move all terms to the left:
5x/x+4-(3x+1)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
5x/x-3x-1+4=0
We multiply all the terms by the denominator
5x-3x*x-1*x+4*x=0
We add all the numbers together, and all the variables
8x-3x*x=0
Wy multiply elements
-3x^2+8x=0
a = -3; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-3)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-3}=\frac{-16}{-6} =2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-3}=\frac{0}{-6} =0 $
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