5x/x+2-3x-4/x+2

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Solution for 5x/x+2-3x-4/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5*x)/x-(3*x)-(4/x)+2+2 = 0

(5*x)/x-3*x-4*x^-1+2+2 = 0

9*x^0-3*x^1-4*x^-1 = 0

(9*x^1-3*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(9*x^1-3*x^2-4*x^0) = 0

x^1

9*x-3*x^2-4 = 0

9*x-3*x^2-4 = 0

DELTA = 9^2-(-4*(-3)*4)

DELTA = 33

DELTA > 0

x = (33^(1/2)-9)/(-3*2) or x = (-33^(1/2)-9)/(-3*2)

x = (33^(1/2)-9)/(-6) or x = (33^(1/2)+9)/6

x in { (33^(1/2)-9)/(-6), (33^(1/2)+9)/6} 

x in { (33^(1/2)-9)/(-6), (33^(1/2)+9)/6 }

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