5x-9/3+x2=10

Solution for 5x-9/3+x2=10 equation:

5x-9/3+x2=10

We move all terms to the left:

5x-9/3+x2-(10)=0

determiningTheFunctionDomain
5x+x2-10-9/3=0

We add all the numbers together, and all the variables

x^2+5x-13=0

a = 1; b = 5; c = -13;
Δ = b2-4ac
Δ = 52-4·1·(-13)
Δ = 77
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{77}}{2*1}=\frac{-5-\sqrt{77}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{77}}{2*1}=\frac{-5+\sqrt{77}}{2}
$