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5x-8-2x+14=x+12+2(x-3)
We move all terms to the left:
5x-8-2x+14-(x+12+2(x-3))=0
We add all the numbers together, and all the variables
3x-(x+12+2(x-3))+6=0
We calculate terms in parentheses: -(x+12+2(x-3)), so:We get rid of parentheses
x+12+2(x-3)
determiningTheFunctionDomain x+2(x-3)+12
We multiply parentheses
x+2x-6+12
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
3x-3x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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