5x-8+3x=2(2x-4)+4x

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Solution for 5x-8+3x=2(2x-4)+4x equation: 



5x-8+3x=2(2x-4)+4x

We move all terms to the left:

5x-8+3x-(2(2x-4)+4x)=0

We add all the numbers together, and all the variables

8x-(2(2x-4)+4x)-8=0



We calculate terms in parentheses: -(2(2x-4)+4x), so:

2(2x-4)+4x

We add all the numbers together, and all the variables

4x+2(2x-4)

We multiply parentheses

4x+4x-8

We add all the numbers together, and all the variables

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

8x-8x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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