5x-7x+6=-2x(x-3)

Solution for 5x-7x+6=-2x(x-3) equation:

5x-7x+6=-2x(x-3)

We move all terms to the left:

5x-7x+6-(-2x(x-3))=0

We add all the numbers together, and all the variables

-2x-(-2x(x-3))+6=0


We calculate terms in parentheses: -(-2x(x-3)), so:

-2x(x-3)

We multiply parentheses

-2x^2+6x

Back to the equation:

-(-2x^2+6x)


We get rid of parentheses

2x^2-6x-2x+6=0

We add all the numbers together, and all the variables

2x^2-8x+6=0

a = 2; b = -8; c = +6;
Δ = b2-4ac
Δ = -82-4·2·6
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*2}=\frac{4}{4}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*2}=\frac{12}{4}
=3
$