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5x-6=(x+12)+(x-3)
We move all terms to the left:
5x-6-((x+12)+(x-3))=0
We calculate terms in parentheses: -((x+12)+(x-3)), so:We get rid of parentheses
(x+12)+(x-3)
We get rid of parentheses
x+x+12-3
We add all the numbers together, and all the variables
2x+9
Back to the equation:
-(2x+9)
5x-2x-9-6=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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