5x-6/3x2+11/3x2=1/3x

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Solution for 5x-6/3x2+11/3x2=1/3x equation: 


x in (-oo:+oo)

(11/3)*x^2-((6/3)*x^2)+5*x = (1/3)*x // - (1/3)*x

(11/3)*x^2-((6/3)*x^2)+5*x-((1/3)*x) = 0

(11/3)*x^2-2*x^2+5*x+(-1/3)*x = 0

5/3*x^2+14/3*x = 0

DELTA = (14/3)^2-(0*5/3*4)

DELTA = 196/9

DELTA > 0

x = ((196/9)^(1/2)-14/3)/(5/3*2) or x = (-(196/9)^(1/2)-14/3)/(5/3*2)

x = 0 or x = -14/5

x in { -14/5, 0 }

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