5x-6/(x-1)(x-3)=4x-4/(x-1)(x-3)

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Solution for 5x-6/(x-1)(x-3)=4x-4/(x-1)(x-3) equation:


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

5*x-((6/(x-1))*(x-3)) = 4*x-((4/(x-1))*(x-3)) // - 4*x-((4/(x-1))*(x-3))

(4/(x-1))*(x-3)-((6/(x-1))*(x-3))+5*x-(4*x) = 0

(4/(x-1))*(x-3)-6*(x-1)^-1*(x-3)+5*x-4*x = 0

(-6*(x-3))/(x-1)+(4*(x-3))/(x-1)+5*x-4*x = 0

(-6*(x-3))/(x-1)+(4*(x-3))/(x-1)+(5*x*(x-1))/(x-1)+(-4*x*(x-1))/(x-1) = 0

4*(x-3)-6*(x-3)+5*x*(x-1)-4*x*(x-1) = 0

5*x^2-4*x^2-2*x-5*x+4*x+6 = 0

5*x^2-4*x^2-7*x+4*x+6 = 0

x^2-3*x+6 = 0

x^2-3*x+6 = 0

x^2-3*x+6 = 0

DELTA = (-3)^2-(1*4*6)

DELTA = -15

DELTA < 0

1 = 0

1/(x-1) = 0

1/(x-1) = 0 // * x-1

1 = 0

x belongs to the empty set

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