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5x-5(2x+1)=-(3-2x)
We move all terms to the left:
5x-5(2x+1)-(-(3-2x))=0
We add all the numbers together, and all the variables
5x-5(2x+1)-(-(-2x+3))=0
We multiply parentheses
5x-10x-(-(-2x+3))-5=0
We calculate terms in parentheses: -(-(-2x+3)), so:We add all the numbers together, and all the variables
-(-2x+3)
We get rid of parentheses
2x-3
Back to the equation:
-(2x-3)
-5x-(2x-3)-5=0
We get rid of parentheses
-5x-2x+3-5=0
We add all the numbers together, and all the variables
-7x-2=0
We move all terms containing x to the left, all other terms to the right
-7x=2
x=2/-7
x=-2/7
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