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5x-4/x+2=3x+1/x-1
We move all terms to the left:
5x-4/x+2-(3x+1/x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-1)!=0We get rid of parentheses
x∈R
5x-4/x-3x-1/x+1+2=0
We multiply all the terms by the denominator
5x*x-3x*x+1*x+2*x-4-1=0
We add all the numbers together, and all the variables
3x+5x*x-3x*x-5=0
Wy multiply elements
5x^2-3x^2+3x-5=0
We add all the numbers together, and all the variables
2x^2+3x-5=0
a = 2; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·2·(-5)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7}{2*2}=\frac{-10}{4} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7}{2*2}=\frac{4}{4} =1 $
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