5x-4/4x=9/4-7/x

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Solution for 5x-4/4x=9/4-7/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x-((4/4)*x) = 9/4-(7/x) // - 9/4-(7/x)

5*x-((4/4)*x)+7/x-(9/4) = 0

5*x-x+7/x-9/4 = 0

4*x^1+7*x^-1-9/4*x^0 = 0

(4*x^2-9/4*x^1+7*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-9/4*x^1+7*x^0) = 0

x^1

4*x^2+(-9/4)*x+7 = 0

4*x^2+(-9/4)*x+7 = 0

DELTA = (-9/4)^2-(4*4*7)

DELTA = -1711/16

DELTA < 0

x in { } 

x belongs to the empty set

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