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5x-4(5-3x)-3(8+2(x+1)+2x)=-5(1-8x)
We move all terms to the left:
5x-4(5-3x)-3(8+2(x+1)+2x)-(-5(1-8x))=0
We add all the numbers together, and all the variables
5x-4(-3x+5)-3(8+2(x+1)+2x)-(-5(-8x+1))=0
We multiply parentheses
5x+12x-3(8+2(x+1)+2x)-(-5(-8x+1))-20=0
We calculate terms in parentheses: -(-5(-8x+1)), so:We add all the numbers together, and all the variables
-5(-8x+1)
We multiply parentheses
40x-5
Back to the equation:
-(40x-5)
17x-3(8+2(x+1)+2x)-(40x-5)-20=0
We get rid of parentheses
17x-3(8+2(x+1)+2x)-40x+5-20=0
We add all the numbers together, and all the variables
-23x-3(8+2(x+1)+2x)-15=0
We move all terms containing x to the left, all other terms to the right
-23x-3(8+2(x+1)+2x)=15
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