5x-4(3-2x)=4(x-5)-10

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Solution for 5x-4(3-2x)=4(x-5)-10 equation: 



5x-4(3-2x)=4(x-5)-10

We move all terms to the left:

5x-4(3-2x)-(4(x-5)-10)=0

We add all the numbers together, and all the variables

5x-4(-2x+3)-(4(x-5)-10)=0

We multiply parentheses

5x+8x-(4(x-5)-10)-12=0



We calculate terms in parentheses: -(4(x-5)-10), so:

4(x-5)-10

We multiply parentheses

4x-20-10

We add all the numbers together, and all the variables

4x-30

Back to the equation:

-(4x-30)



We add all the numbers together, and all the variables

13x-(4x-30)-12=0

We get rid of parentheses

13x-4x+30-12=0

We add all the numbers together, and all the variables

9x+18=0

We move all terms containing x to the left, all other terms to the right

9x=-18

x=-18/9

x=-2

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