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5x-3/10x=3
We move all terms to the left:
5x-3/10x-(3)=0
Domain of the equation: 10x!=0We multiply all the terms by the denominator
x!=0/10
x!=0
x∈R
5x*10x-3*10x-3=0
Wy multiply elements
50x^2-30x-3=0
a = 50; b = -30; c = -3;
Δ = b2-4ac
Δ = -302-4·50·(-3)
Δ = 1500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1500}=\sqrt{100*15}=\sqrt{100}*\sqrt{15}=10\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{15}}{2*50}=\frac{30-10\sqrt{15}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{15}}{2*50}=\frac{30+10\sqrt{15}}{100} $
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