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5x-3+x=3(2x-2)+3
We move all terms to the left:
5x-3+x-(3(2x-2)+3)=0
We add all the numbers together, and all the variables
6x-(3(2x-2)+3)-3=0
We calculate terms in parentheses: -(3(2x-2)+3), so:We get rid of parentheses
3(2x-2)+3
We multiply parentheses
6x-6+3
We add all the numbers together, and all the variables
6x-3
Back to the equation:
-(6x-3)
6x-6x+3-3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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