5x-3+x+12=x-8+4x+20

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Solution for 5x-3+x+12=x-8+4x+20 equation: 



5x-3+x+12=x-8+4x+20

We move all terms to the left:

5x-3+x+12-(x-8+4x+20)=0

We add all the numbers together, and all the variables

5x+x-(5x+12)-3+12=0

We add all the numbers together, and all the variables

6x-(5x+12)+9=0

We get rid of parentheses

6x-5x-12+9=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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