5x-3+7x=3(2x-5)

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Solution for 5x-3+7x=3(2x-5) equation: 



5x-3+7x=3(2x-5)

We move all terms to the left:

5x-3+7x-(3(2x-5))=0

We add all the numbers together, and all the variables

12x-(3(2x-5))-3=0



We calculate terms in parentheses: -(3(2x-5)), so:

3(2x-5)

We multiply parentheses

6x-15

Back to the equation:

-(6x-15)



We get rid of parentheses

12x-6x+15-3=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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