5x-3+2x=3+x-12(-2)

Solution for 5x-3+2x=3+x-12(-2) equation:

5x-3+2x=3+x-12(-2)

We move all terms to the left:

5x-3+2x-(3+x-12(-2))=0

We add all the numbers together, and all the variables

7x-(3+x-12(-2))-3=0


We calculate terms in parentheses: -(3+x-12(-2)), so:

3+x-12(-2)

determiningTheFunctionDomain
x+3-12(-2)

We add all the numbers together, and all the variables

x+27

Back to the equation:

-(x+27)


We get rid of parentheses

7x-x-27-3=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5