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5x-3(x-6)=2(x+3)+12
We move all terms to the left:
5x-3(x-6)-(2(x+3)+12)=0
We multiply parentheses
5x-3x-(2(x+3)+12)+18=0
We calculate terms in parentheses: -(2(x+3)+12), so:We add all the numbers together, and all the variables
2(x+3)+12
We multiply parentheses
2x+6+12
We add all the numbers together, and all the variables
2x+18
Back to the equation:
-(2x+18)
2x-(2x+18)+18=0
We get rid of parentheses
2x-2x-18+18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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