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5x-2=6-2(4-x)+3
We move all terms to the left:
5x-2-(6-2(4-x)+3)=0
We add all the numbers together, and all the variables
5x-(6-2(-1x+4)+3)-2=0
We calculate terms in parentheses: -(6-2(-1x+4)+3), so:We get rid of parentheses
6-2(-1x+4)+3
determiningTheFunctionDomain -2(-1x+4)+6+3
We add all the numbers together, and all the variables
-2(-1x+4)+9
We multiply parentheses
2x-8+9
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
5x-2x-1-2=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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