5x-2+(4x-4)=1+(3x-3)

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Solution for 5x-2+(4x-4)=1+(3x-3) equation: 



5x-2+(4x-4)=1+(3x-3)

We move all terms to the left:

5x-2+(4x-4)-(1+(3x-3))=0

We get rid of parentheses

5x+4x-(1+(3x-3))-4-2=0



We calculate terms in parentheses: -(1+(3x-3)), so:

1+(3x-3)

determiningTheFunctionDomain
(3x-3)+1

We get rid of parentheses

3x-3+1

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

9x-(3x-2)-6=0

We get rid of parentheses

9x-3x+2-6=0

We add all the numbers together, and all the variables

6x-4=0

We move all terms containing x to the left, all other terms to the right

6x=4

x=4/6

x=2/3

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