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5x-2(x-5)=5x-(2-x)
We move all terms to the left:
5x-2(x-5)-(5x-(2-x))=0
We add all the numbers together, and all the variables
5x-2(x-5)-(5x-(-1x+2))=0
We multiply parentheses
5x-2x-(5x-(-1x+2))+10=0
We calculate terms in parentheses: -(5x-(-1x+2)), so:We add all the numbers together, and all the variables
5x-(-1x+2)
We get rid of parentheses
5x+1x-2
We add all the numbers together, and all the variables
6x-2
Back to the equation:
-(6x-2)
3x-(6x-2)+10=0
We get rid of parentheses
3x-6x+2+10=0
We add all the numbers together, and all the variables
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4
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