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5x-2(x-1)=2-(x-5)
We move all terms to the left:
5x-2(x-1)-(2-(x-5))=0
We multiply parentheses
5x-2x-(2-(x-5))+2=0
We calculate terms in parentheses: -(2-(x-5)), so:We add all the numbers together, and all the variables
2-(x-5)
determiningTheFunctionDomain -(x-5)+2
We get rid of parentheses
-x+5+2
We add all the numbers together, and all the variables
-1x+7
Back to the equation:
-(-1x+7)
3x-(-1x+7)+2=0
We get rid of parentheses
3x+1x-7+2=0
We add all the numbers together, and all the variables
4x-5=0
We move all terms containing x to the left, all other terms to the right
4x=5
x=5/4
x=1+1/4
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