5x-2(x+6)+2=4(x-2)+13

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Solution for 5x-2(x+6)+2=4(x-2)+13 equation: 



5x-2(x+6)+2=4(x-2)+13

We move all terms to the left:

5x-2(x+6)+2-(4(x-2)+13)=0

We multiply parentheses

5x-2x-(4(x-2)+13)-12+2=0



We calculate terms in parentheses: -(4(x-2)+13), so:

4(x-2)+13

We multiply parentheses

4x-8+13

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We add all the numbers together, and all the variables

3x-(4x+5)-10=0

We get rid of parentheses

3x-4x-5-10=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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