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5x-2(x+2)=11-(2x+5)
We move all terms to the left:
5x-2(x+2)-(11-(2x+5))=0
We multiply parentheses
5x-2x-(11-(2x+5))-4=0
We calculate terms in parentheses: -(11-(2x+5)), so:We add all the numbers together, and all the variables
11-(2x+5)
determiningTheFunctionDomain -(2x+5)+11
We get rid of parentheses
-2x-5+11
We add all the numbers together, and all the variables
-2x+6
Back to the equation:
-(-2x+6)
3x-(-2x+6)-4=0
We get rid of parentheses
3x+2x-6-4=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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