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5x-2(4-3x)=5x+4(x-3)
We move all terms to the left:
5x-2(4-3x)-(5x+4(x-3))=0
We add all the numbers together, and all the variables
5x-2(-3x+4)-(5x+4(x-3))=0
We multiply parentheses
5x+6x-(5x+4(x-3))-8=0
We calculate terms in parentheses: -(5x+4(x-3)), so:We add all the numbers together, and all the variables
5x+4(x-3)
We multiply parentheses
5x+4x-12
We add all the numbers together, and all the variables
9x-12
Back to the equation:
-(9x-12)
11x-(9x-12)-8=0
We get rid of parentheses
11x-9x+12-8=0
We add all the numbers together, and all the variables
2x+4=0
We move all terms containing x to the left, all other terms to the right
2x=-4
x=-4/2
x=-2
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