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5x-13/3x+3=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
5x*3x+3*3x-13=0
Wy multiply elements
15x^2+9x-13=0
a = 15; b = 9; c = -13;
Δ = b2-4ac
Δ = 92-4·15·(-13)
Δ = 861
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{861}}{2*15}=\frac{-9-\sqrt{861}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{861}}{2*15}=\frac{-9+\sqrt{861}}{30} $
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