5x-(x+4)=-10-2(x-8)

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Solution for 5x-(x+4)=-10-2(x-8) equation: 



5x-(x+4)=-10-2(x-8)

We move all terms to the left:

5x-(x+4)-(-10-2(x-8))=0

We get rid of parentheses

5x-x-(-10-2(x-8))-4=0



We calculate terms in parentheses: -(-10-2(x-8)), so:

-10-2(x-8)

determiningTheFunctionDomain
-2(x-8)-10

We multiply parentheses

-2x+16-10

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

4x-(-2x+6)-4=0

We get rid of parentheses

4x+2x-6-4=0

We add all the numbers together, and all the variables

6x-10=0

We move all terms containing x to the left, all other terms to the right

6x=10

x=10/6

x=1+2/3

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