5x-(7-(2x-1))=3(x5)+4(x+3)

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Solution for 5x-(7-(2x-1))=3(x5)+4(x+3) equation: 



5x-(7-(2x-1))=3(x5)+4(x+3)

We move all terms to the left:

5x-(7-(2x-1))-(3(x5)+4(x+3))=0



We calculate terms in parentheses: -(7-(2x-1)), so:

7-(2x-1)

determiningTheFunctionDomain
-(2x-1)+7

We get rid of parentheses

-2x+1+7

We add all the numbers together, and all the variables

-2x+8

Back to the equation:

-(-2x+8)





We calculate terms in parentheses: -(3x5+4(x+3)), so:

3x5+4(x+3)

We add all the numbers together, and all the variables

3x^5+4(x+3)

We multiply parentheses

3x^5+4x+12

We do not support expression: x^5

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