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5x-(3-2x)=33+2(x-8)
We move all terms to the left:
5x-(3-2x)-(33+2(x-8))=0
We add all the numbers together, and all the variables
5x-(-2x+3)-(33+2(x-8))=0
We get rid of parentheses
5x+2x-(33+2(x-8))-3=0
We calculate terms in parentheses: -(33+2(x-8)), so:We add all the numbers together, and all the variables
33+2(x-8)
determiningTheFunctionDomain 2(x-8)+33
We multiply parentheses
2x-16+33
We add all the numbers together, and all the variables
2x+17
Back to the equation:
-(2x+17)
7x-(2x+17)-3=0
We get rid of parentheses
7x-2x-17-3=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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