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5x+60+(x2+9x)=180
We move all terms to the left:
5x+60+(x2+9x)-(180)=0
We add all the numbers together, and all the variables
(+x^2+9x)+5x+60-180=0
We add all the numbers together, and all the variables
(+x^2+9x)+5x-120=0
We get rid of parentheses
x^2+9x+5x-120=0
We add all the numbers together, and all the variables
x^2+14x-120=0
a = 1; b = 14; c = -120;
Δ = b2-4ac
Δ = 142-4·1·(-120)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*1}=\frac{12}{2} =6 $
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