5x+5(x+2)=(x+4)+31

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Solution for 5x+5(x+2)=(x+4)+31 equation: 



5x+5(x+2)=(x+4)+31

We move all terms to the left:

5x+5(x+2)-((x+4)+31)=0

We multiply parentheses

5x+5x-((x+4)+31)+10=0



We calculate terms in parentheses: -((x+4)+31), so:

(x+4)+31

We get rid of parentheses

x+4+31

We add all the numbers together, and all the variables

x+35

Back to the equation:

-(x+35)



We add all the numbers together, and all the variables

10x-(x+35)+10=0

We get rid of parentheses

10x-x-35+10=0

We add all the numbers together, and all the variables

9x-25=0

We move all terms containing x to the left, all other terms to the right

9x=25

x=25/9

x=2+7/9

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