5x+4+12=x+12+2(x-3)

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Solution for 5x+4+12=x+12+2(x-3) equation: 



5x+4+12=x+12+2(x-3)

We move all terms to the left:

5x+4+12-(x+12+2(x-3))=0

We add all the numbers together, and all the variables

5x-(x+12+2(x-3))+16=0



We calculate terms in parentheses: -(x+12+2(x-3)), so:

x+12+2(x-3)

determiningTheFunctionDomain
x+2(x-3)+12

We multiply parentheses

x+2x-6+12

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

5x-3x-6+16=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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