5x+3=2(x2-x+3)-2x2

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Solution for 5x+3=2(x2-x+3)-2x2 equation: 



5x+3=2(x2-x+3)-2x^2

We move all terms to the left:

5x+3-(2(x2-x+3)-2x^2)=0

We add all the numbers together, and all the variables

-(2(+x^2-1x+3)-2x^2)+5x+3=0



We calculate terms in parentheses: -(2(+x^2-1x+3)-2x^2), so:

2(+x^2-1x+3)-2x^2

We add all the numbers together, and all the variables

-2x^2+2(+x^2-1x+3)

We multiply parentheses

-2x^2+2x^2-2x+6

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

5x-(-2x+6)+3=0

We get rid of parentheses

5x+2x-6+3=0

We add all the numbers together, and all the variables

7x-3=0

We move all terms containing x to the left, all other terms to the right

7x=3

x=3/7

x=3/7

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