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5x+3-3x=+2(x+3)-5
We move all terms to the left:
5x+3-3x-(+2(x+3)-5)=0
We add all the numbers together, and all the variables
2x-(+2(x+3)-5)+3=0
We calculate terms in parentheses: -(+2(x+3)-5), so:We get rid of parentheses
+2(x+3)-5
determiningTheFunctionDomain 2(x+3)-5
We multiply parentheses
2x+6-5
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
2x-2x-1+3=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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