5x+3-2(3x-1)=2(7x-4)+15-3x

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Solution for 5x+3-2(3x-1)=2(7x-4)+15-3x equation: 



5x+3-2(3x-1)=2(7x-4)+15-3x

We move all terms to the left:

5x+3-2(3x-1)-(2(7x-4)+15-3x)=0

We multiply parentheses

5x-6x-(2(7x-4)+15-3x)+2+3=0



We calculate terms in parentheses: -(2(7x-4)+15-3x), so:

2(7x-4)+15-3x

determiningTheFunctionDomain
2(7x-4)-3x+15

We add all the numbers together, and all the variables

-3x+2(7x-4)+15

We multiply parentheses

-3x+14x-8+15

We add all the numbers together, and all the variables

11x+7

Back to the equation:

-(11x+7)



We add all the numbers together, and all the variables

-1x-(11x+7)+5=0

We get rid of parentheses

-1x-11x-7+5=0

We add all the numbers together, and all the variables

-12x-2=0

We move all terms containing x to the left, all other terms to the right

-12x=2

x=2/-12

x=-1/6

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