5x+3(x-2)=1/2(10x-12)

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Solution for 5x+3(x-2)=1/2(10x-12) equation: 



5x+3(x-2)=1/2(10x-12)

We move all terms to the left:

5x+3(x-2)-(1/2(10x-12))=0



Domain of the equation: 2(10x-12))!=0

x∈R



We multiply parentheses

5x+3x-(1/2(10x-12))-6=0

We multiply all the terms by the denominator


5x*2(10x-12))+3x*2(10x-12))-(1-6*2(10x-12))=0

We add all the numbers together, and all the variables

5x*2(10x-12))+3x*2(10x-12))-(1-6*2(10x=0

Wy multiply elements

20x^3(1-12))-(1-6*2(10x=0

We do not support expression: x^3(1

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