5x+3(x-1)=8(x+2)-x

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Solution for 5x+3(x-1)=8(x+2)-x equation: 



5x+3(x-1)=8(x+2)-x

We move all terms to the left:

5x+3(x-1)-(8(x+2)-x)=0

We multiply parentheses

5x+3x-(8(x+2)-x)-3=0



We calculate terms in parentheses: -(8(x+2)-x), so:

8(x+2)-x

We add all the numbers together, and all the variables

-1x+8(x+2)

We multiply parentheses

-1x+8x+16

We add all the numbers together, and all the variables

7x+16

Back to the equation:

-(7x+16)



We add all the numbers together, and all the variables

8x-(7x+16)-3=0

We get rid of parentheses

8x-7x-16-3=0

We add all the numbers together, and all the variables

x-19=0

We move all terms containing x to the left, all other terms to the right

x=19

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