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5x+2=3x(x+14)
We move all terms to the left:
5x+2-(3x(x+14))=0
We calculate terms in parentheses: -(3x(x+14)), so:We get rid of parentheses
3x(x+14)
We multiply parentheses
3x^2+42x
Back to the equation:
-(3x^2+42x)
-3x^2+5x-42x+2=0
We add all the numbers together, and all the variables
-3x^2-37x+2=0
a = -3; b = -37; c = +2;
Δ = b2-4ac
Δ = -372-4·(-3)·2
Δ = 1393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1393}}{2*-3}=\frac{37-\sqrt{1393}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1393}}{2*-3}=\frac{37+\sqrt{1393}}{-6} $
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