5x+2=27+(3x-1)

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Solution for 5x+2=27+(3x-1) equation:



5x+2=27+(3x-1)
We move all terms to the left:
5x+2-(27+(3x-1))=0
We calculate terms in parentheses: -(27+(3x-1)), so:
27+(3x-1)
determiningTheFunctionDomain (3x-1)+27
We get rid of parentheses
3x-1+27
We add all the numbers together, and all the variables
3x+26
Back to the equation:
-(3x+26)
We get rid of parentheses
5x-3x-26+2=0
We add all the numbers together, and all the variables
2x-24=0
We move all terms containing x to the left, all other terms to the right
2x=24
x=24/2
x=12

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