5x+20/3x+4=3

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Solution for 5x+20/3x+4=3 equation: 



5x+20/3x+4=3

We move all terms to the left:

5x+20/3x+4-(3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

5x+20/3x+1=0

We multiply all the terms by the denominator


5x*3x+1*3x+20=0

Wy multiply elements

15x^2+3x+20=0

a = 15; b = 3; c = +20;
Δ = b2-4ac
Δ = 32-4·15·20
Δ = -1191
Delta is less than zero, so there is no solution for the equation

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